About

Asador De Pollos Federico García Lorca in Burgos is a go-to spot for a satisfying, affordable lunch. Known for its flavorful chicken dishes, this casual eatery offers meals that won't break the bank, with prices ranging from 10 to 20 EUR per person. With a strong 4.6 rating on Google, patrons appreciate the deliciously seasoned bird and the convenience of takeaway service. Whether you're grabbing a quick bite or savoring your meal, this restaurant promises a delightful experience without the fuss.

Price

$$$$ 10 - 20 EUR

Meals

Lunch

Services

Takeaway

Payment

Payment by credit card, Payment by debit card, NFC payment

Atmosphere

Casual

Reviews and Ratings

Write a review
4.7
based on 301 review
4.7/5 301 review
Jhillian Diaz
Jhillian Diaz
2 months ago on Google
  • Food: 5
  • Service: 5
  • Atmosphere: 5

Muy buen pollo y muy majos los que te sirven

Miguel Martín Cepeda
Miguel Martín Cepeda
2 months ago on Google
  • Food: 5
  • Service: 5
  • Atmosphere: 5

me ha encantado verte

Óscar Morales
Óscar Morales
2 months ago on Google
  • Food: 5
  • Service: 5
  • Atmosphere: 5

Fuimos por recomendación de unos amigos los pollos asados muy buenos bien asados ,con mucha salsita repetiremos seguro un sitio de diez

Frequently Asked Questions

  • What is the address of Asador De Pollos Federico García Lorca?
    Asador De Pollos Federico García Lorca is located at C. Federico García Lorca, 9, 09007, Burgos, Spain.
  • How to get here by public transport?
    The nearest public transport options provide quick and easy access:
    • Bus stop Burgos (Gamonal) (625 m walk)
    • Bus stop Burgos - Capiscol (423 m walk)
    • Train station Burgos - Rosa Manzano (2.28 km walk)
  • How is Asador De Pollos Federico García Lorca rated by visitors?
    Asador De Pollos Federico García Lorca has an average rating of 4.7 based on 301 review across platforms such as Google.
  • What is the average price for a meal at Asador De Pollos Federico García Lorca?
    The average price for a meal is 10 - 20 EUR (it is cheap - $).